Answer:
Number of neutrons in silicon \[({{n}_{1}})=2814=14\] Number of neutrons in phosphorus \[({{n}_{2}})\text{ }3115=16\] Ratio \[=\frac{{{n}_{1}}}{{{n}_{2}}}=\frac{14}{16}\]or 7 : 8 Therefore, the ratio of number of neutrons in silicon to phosphorus is\[7:8\].
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