A) \[64\,\,g\]
B) \[63\,\,g\]
C) \[65\,\,g\]
D) \[66\,\,g\]
Correct Answer: B
Solution :
\[G.M.W.\] of\[NaHC{{O}_{3}}\] \[=23+1+12+16\times 3=84\,\,g\] \[1\] gram mole of\[NaHC{{O}_{3}}\], weights\[=84\,\,g\] \[0.75\] gram mole of\[NaHC{{O}_{3}}\]weights\[=\] \[0.75\times 84=63\,\,g\]You need to login to perform this action.
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