A) \[200\,\,g\]
B) \[230\,\,g\]
C) \[240\,\,g\]
D) \[250\,\,g\]
Correct Answer: D
Solution :
Formula weight of\[CaC{{O}_{3}}\] \[=40+12+3\times 16=100\,\,a.m.u.\] \[1\] mole of\[CaC{{O}_{3}}=100\,\,g\] Hence, \[2.5\] moles of\[CaC{{O}_{3}}\] \[=2.5\times 100=250\,\,g\]You need to login to perform this action.
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