A) \[80{}^\circ C\]
B) \[100{}^\circ C\]
C) \[120{}^\circ C\]
D) \[160{}^\circ C\]
Correct Answer: B
Solution :
\[Q=kA\,\frac{\left( {{t}_{1}}-{{t}_{2}} \right)}{L}\] \[{{t}_{1}}-{{t}_{2}}=\frac{QL}{kA}=\frac{6\times {{10}^{3}}}{100\times 60\times 100\times 10\times {{10}^{-\,4}}}\] \[=\,100{}^\circ C\]
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