A) d
B) \[{{d}^{2}}\]
C) \[{{d}^{3}}\]
D) \[{{d}^{4}}\]
Correct Answer: D
Solution :
\[\frac{T}{J}=\frac{G\theta }{l}\] \[\theta =\frac{Tl}{GJ}\infty \frac{1}{{{d}^{4}}}\]
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