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JEE Main & Advanced Physics Wave Mechanics Question Bank Basics of Mechanical Waves

  • question_answer
    The phase difference between two points separated by 1m in a wave of frequency 120 Hz is \[{{90}^{o}}\]. The wave velocity is [KCET 1999]

    A)            180 m/s                                  

    B)            240 m/s

    C)            480 m/s                                  

    D)            720 m/s

    Correct Answer: C

    Solution :

                Path difference \[\Delta =\frac{\lambda }{2\pi }\times \varphi \] Þ \[1=\frac{\lambda }{2\pi }\times \frac{\pi }{2}\]Þ l = 4m Hence \[v=n\lambda \]= \[120\times 4=480\] \[m/s\]


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