JEE Main & Advanced Physics Wave Mechanics Question Bank Basics of Mechanical Waves

  • question_answer
    The frequency of a tunning fork is 384 per second and velocity of sound in air is 352 m/s. How far the sound has traversed while fork completes 36 vibration  [KCET 2001]

    A)            3 m

    B)            13 m

    C)            23 m                                        

    D)            33 m

    Correct Answer: D

    Solution :

               \[\lambda =\frac{v}{n}=\frac{352}{384}\]; during 1 vibration of fork sound will travel \[\frac{352}{384}m\]during 36 vibration of fork sound will travel \[\frac{352}{384}\times 36=33\]\[m\]


You need to login to perform this action.
You will be redirected in 3 sec spinner