A) 90 sec?1
B) 180s?1
C) 120 sec?1
D) 360 sec?1
Correct Answer: A
Solution :
The minimum distance between compression and rarefaction of the wire \[l=\frac{\lambda }{4}\]\[\therefore \] Wave length \[\lambda =4l\] Now by \[v=n\lambda \Rightarrow n=\frac{360}{4\times 1}=90\]\[{{\sec }^{-1}}.\]
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