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JEE Main & Advanced Physics Wave Mechanics Question Bank Beats

  • question_answer
    Two tuning forks of frequencies 256 and 258 vibrations/sec are sounded together, then time interval between consecutive maxima heard by the observer is [MP PET/PMT 1988]

    A)            2 sec                                        

    B)            0.5 sec

    C)            250 sec                                    

    D)            252 sec

    Correct Answer: B

    Solution :

               \[T=\frac{1}{258-256}\]= \[0.5\sec \]


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