2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Wave Mechanics

JEE Main & Advanced Physics Wave Mechanics Question Bank Beats

  • question_answer
    Beats are produced by two waves given by \[{{y}_{1}}=a\sin 2000\,\pi t\] and \[{{y}_{2}}=a\sin 2008\,\pi t\]. The number of beats heard per second is                                                     [CPMT 1990; DCE 1999]

    A)            Zero                                         

    B)            One

    C)            Four                                         

    D)            Eight

    Correct Answer: C

    Solution :

                       Number of beats per second = \[{{n}_{1}}\tilde{\ }{{n}_{2}}\] \[{{\omega }_{1}}=2000\pi =2\pi {{n}_{1}}\] Þ n1 = 1000 and \[{{\omega }_{2}}=2008\pi =2\pi {{n}_{2}}\] Þ n2 = 1004 Number of beats heard per sec\[=1004-1000=4\]


You need to login to perform this action.
You will be redirected in 3 sec spinner