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JEE Main & Advanced Physics Wave Mechanics Question Bank Beats

  • question_answer
    A tuning fork vibrates with 2 beats in 0.04 second. The frequency of the fork is [AFMC 2003]

    A)            50 Hz                                       

    B)            100 Hz

    C)            80 Hz                                       

    D)            None of these

    Correct Answer: A

    Solution :

               Frequency = \[\frac{\text{Number of beats}}{\text{Time}}=\frac{2}{0.04}=50\,\,Hz\]


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