A) 7th term
B) 5th term
C) 8th term
D) 6th term
Correct Answer: C
Solution :
\[{{(1+x)}^{27/5}}\] \[{{T}_{r+1}}=\frac{n(n-1)(n-2)......(n-r+1)}{r!}{{(x)}^{r}}\] For first negative term\[n-r+1<0\]; \[r>\frac{32}{5}\] . \ First negative term is 8th term.You need to login to perform this action.
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