A) \[C{{H}_{3}}-C\equiv C-H\]
B) \[C{{H}_{3}}-CH=CH-C{{H}_{3}}\]
C) \[C{{H}_{2}}=CH-CH=C{{H}_{2}}\]
D) \[HC\equiv CH\]
Correct Answer: A
Solution :
\[\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\underset{sp}{\mathop{C}}\,\equiv \underset{sp\,\,\,\,\,\,\,\,\,\,\,}{\mathop{C-H}}\,\]
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