question_answer

Homolytic fission of C - C bond in ethane gives an intermediate in which carbon is [IIT-JEE 1992]

A) \[s{{p}^{3}}\] hybridised

B) \[s{{p}^{2}}\]hybridized

C) \[sp\] hybridised

D) \[s{{p}^{2}}d\] hybridized

Correct Answer: B

Solution :

           \[C{{H}_{3}}-C{{H}_{3}}\underset{\text{bond fission}}{\mathop{\xrightarrow{\text{Homolytic}}}}\,\,\underset{\text{Methyl}\,\text{free}\,\text{radicals}}{\mathop{CH_{3}^{\bullet }\,+\,CH_{3}^{\bullet }}}\,\]            Free radical is formed which is \[s{{p}^{2}}\]-hybridized.