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JEE Main & Advanced Chemistry GOC Question Bank Bonding and hybridisation inorganic compounds

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    In the reaction \[\begin{matrix}    Br  \\    H  \\ \end{matrix}>\underset{1}{\mathop{C}}\,=\underset{2}{\mathop{C}}\,<\begin{matrix}    Br  \\    H  \\ \end{matrix}\overset{{{H}_{2}}}{\mathop{\xrightarrow[\text{Catalyst}]{}}}\,\underset{3}{\mathop{BrC{{H}_{2}}}}\,\underset{4}{\mathop{C{{H}_{2}}Br}}\,\] The hybridisation states of carbon atoms 1, 2, 3, 4 are [MP PET 1994]

    A) 1 and 2 \[s{{p}^{2}};\] 3 and 4 \[s{{p}^{3}}\]

    B) 1 and 2 \[s{{p}^{2}};\] 3 and 4 \[sp\]

    C) 1, 2, 3 and 4 \[sp\]

    D) 1, 2 \[s{{p}^{3}};\] 3, 4 \[s{{p}^{2}}\]

    Correct Answer: A

    Solution :

    \[\underset{\,\,\,s{{p}^{2}}\,\,\,\,\,\,s{{p}^{2}}}{\mathop{Br-\overset{1}{\mathop{CH=}}\,\overset{2}{\mathop{CH}}\,-Br}}\,\,\underset{\text{Catalyst}}{\mathop{\xrightarrow{{{H}_{2}}}}}\,Br-\underset{s{{p}^{3}}}{\overset{3\,\,\,\,\,}{\mathop{C{{H}_{2}}}}}\,-\underset{s{{p}^{3}}}{\mathop{\overset{4\,\,\,\,\,\,}{\mathop{C{{H}_{2}}}}\,}}\,-Br\]


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