• # question_answer In which of the compounds given below is there more than one kind of hybridisation $(sp,\text{ }s{{p}^{2}},\text{ }s{{p}^{3}})$ for carbon (i) $C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}$ (ii) $C{{H}_{3}}-CH=CH-C{{H}_{3}}$ (iii) $C{{H}_{2}}=CH-CH=C{{H}_{2}}$ (iv) $H-C\equiv C-H$ [CBSE PMT 1995] A) (ii) and (iv) B) (i) and (iv) C) (ii) and (iii) D) (ii)

(i) $\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\overset{s{{p}^{3}}}{\mathop{C{{H}_{2}}}}\,-\overset{s{{p}^{3}}}{\mathop{C{{H}_{2}}}}\,-\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,$      only $s{{p}^{3}}$ hybridized   carbon            (ii) $\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\overset{s{{p}^{2}}}{\mathop{CH}}\,=\overset{s{{p}^{2}}}{\mathop{CH}}\,-\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,$            Both $s{{p}^{2}}$ and $s{{p}^{3}}$ hybridized carbon.            (iii) $\overset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,=\overset{s{{p}^{2}}}{\mathop{CH}}\,-\overset{s{{p}^{2}}}{\mathop{CH}}\,=\overset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,$            Only $s{{p}^{2}}$ hybridized carbon.            (iv) $H-\underset{sp}{\mathop{C}}\,\equiv \underset{sp}{\mathop{C}}\,-H$ Only sp hybridized carbon.