A) \[CH_{3}^{+}\]
B) \[C{{H}_{3}}\]
C) \[{{C}_{2}}H_{5}^{+}\]
D) \[{{C}_{2}}{{H}_{5}}\]
Correct Answer: A
Solution :
Carbonium ions an sp2 hybridized species. \[\begin{matrix} H \\ H \\ \end{matrix}>\begin{matrix} {} \\ \overset{+}{\mathop{C}}\,-H \\ (CH_{3}^{+}) \\ \end{matrix}\] \[\begin{matrix} C{{H}_{3}} \\ H \\ \end{matrix}>\begin{matrix} {} \\ \overset{+}{\mathop{C}}\,-H \\ ({{C}_{2}}H_{5}^{+}) \\ \end{matrix}\]
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