A) \[CH\equiv CH\]
B) \[C{{H}_{2}}=CHCHO\]
C) \[C{{H}_{3}}CH=C{{H}_{2}}\]
D) \[C{{H}_{3}}CH=CHCOOH\]
Correct Answer: C
Solution :
a. \[\underset{2\pi -\text{bonds}}{\mathop{H-C\equiv C-H}}\,\] b. \[\underset{2\pi -\text{bonds}}{\mathop{C{{H}_{2}}=CH-\underset{H}{\mathop{\underset{|}{\mathop{C}}\,}}\,=O}}\,\] c.\[\underset{1\pi \text{ bond}}{\mathop{C{{H}_{3}}CH=C{{H}_{2}}}}\,\] d. \[\underset{2\pi -\text{bonds}}{\mathop{C{{H}_{3}}-CH=CH-}}\,\underset{O}{\mathop{\underset{|\,|}{\mathop{C}}\,}}\,-OH\]
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