A) 2
B) 3
C) 4
D) 6
Correct Answer: D
Solution :
Vinyl acetylene there are 6 unhybridised orbitals. \[\underset{\text{(no}\text{. of unhybridised orbitals)}}{\mathop{\underset{\underset{1}{\mathop{\text{s}{{\text{p}}^{2}}}}\,}{\mathop{C{{H}_{2}}}}\,=\underset{\underset{1}{\mathop{\text{s}{{\text{p}}^{2}}}}\,}{\mathop{CH}}\,-\underset{\underset{\text{2}}{\mathop{\text{sp}}}\,}{\mathop{C}}\,\equiv \underset{\underset{\text{2}}{\mathop{\text{sp}}}\,}{\mathop{CH}}\,}}\,\]
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