A) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\]
B) \[C{{H}_{3}}C\equiv CC{{H}_{3}}\]
C) \[C{{H}_{3}}C\equiv CH\]
D) \[C{{H}_{2}}=CH-CH=C{{H}_{2}}\]
Correct Answer: C
Solution :
Propyne has one acidic hydrogen.
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