A) \[sp,s{{p}^{2}}\,\,\text{and}\,\,s{{p}^{3}}\]
B) \[s{{p}^{2}}\,\,\text{and}\,\,s{{p}^{3}}\]
C) \[s{{p}^{2}}\,\,\text{and}\,\,sp\]
D) \[sp\,\,\text{and}\,\,s{{p}^{3}}\]
Correct Answer: A
Solution :
\[\underset{s{{p}^{2}}}{\mathop{CH}}\,=\underset{sp}{\mathop{C}}\,=\underset{s{{p}^{2}}}{\mathop{CH}}\,-\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,\]
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