A) \[sp,\,sp\]
B) \[s{{p}^{2}},s{{p}^{2}}\]
C) \[s{{p}^{2}},sp\]
D) \[s{{p}^{3}},s{{p}^{2}}\]
Correct Answer: C
Solution :
\[\underset{s{{p}^{2}}\,\,\,\,\,\,\,\,\,sp}{\mathop{\overset{1\,\,\,\,\,\,\,\,}{\mathop{C{{H}_{2}}}}\,=\overset{2}{\mathop{C}}\,}}\,=C{{H}_{2}}\]
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