A) \[HCOOH\]
B) \[{{(N{{H}_{2}})}_{2}}CO\]
C) \[{{(C{{H}_{3}})}_{3}}COH\]
D) \[{{(C{{H}_{3}})}_{3}}CHO\]
Correct Answer: C
Solution :
\[\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,-\underset{\underset{\underset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,\,\,\,\,\,}{\mathop{|\,\,\,\,\,\,\,\,\,\,\,\,\,}}\,}{\overset{\overset{\overset{s{{p}^{3}}}{\mathop{C{{H}_{3}}}}\,\,\,\,\,\,\,}{\mathop{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,}}\,}{\mathop{{{C}^{s{{p}^{3}}}}-}}}\,OH\] All the carbon atoms are \[s{{p}^{3}}\] hybridized.
You need to login to perform this action.
You will be redirected in
3 sec
