A) \[10\times {{10}^{12}}\]
B) \[100\times {{10}^{12}}\]
C) \[1\times {{10}^{12}}\]
D) \[20\times {{10}^{12}}\]
Correct Answer: C
Solution :
\[K=\frac{100}{0.01/100}={{10}^{6}}atm={{10}^{11}}\ N/{{m}^{2}}={{10}^{12}}\ dyne/c{{m}^{2}}\]You need to login to perform this action.
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