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  5. Related to Competitive Exam

8th Class Mathematics Related to Competitive Exam Question Bank Calendar and Clock

  • question_answer
    The year next to 1988 having the same calendar as that of 1988 is-

    A) 1990                           

    B) 1992

    C) 1993               

    D) 1995

    Correct Answer: C

    Solution :

    Starting with 1988, we go on counting the number of odd days till the sum is divisible by 7.
    Year \[\to \] 1988 1989 1990 1991 1992
    Odd days \[\to \] 2 1 1 1 2
    = 7 i.e., Odd days \[\therefore \]Calendar for 1993 the same as that of 1988.      


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