A) 0.196°C
B) 1.960°C
C) 0.96°C
D) 0.0196°C
Correct Answer: A
Solution :
\[W=JQ\] Þ \[mg\,h=J(m.c.\Delta \theta )\] Þ \[\Delta \theta =\frac{g\,h}{Jc}=0.0023\,h=0.0023\times 84=0.196{}^\circ C\]You need to login to perform this action.
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