I. An alcohol undergoes oxidation to produce a carboxylic acid. |
II. An alcohol undergoes esterification. |
III. A carboxylic acid reacts with sodium carbonate. |
IV. Propane undergoes complete combustion. |
A) I and IV only
B) I and II only
C) I, III and IV
D) Only
Correct Answer: D
Solution :
\[C{{H}_{3}}C{{H}_{2}}OH\xrightarrow[Oxidation]{[O]}C{{H}_{3}}COOH\] \[C{{H}_{3}}C{{H}_{2}}OH+C{{H}_{3}}COOH\xrightarrow{{}}C{{H}_{3}}COOC{{H}_{2}}C{{H}_{3}}\]\[2C{{H}_{3}}COOH+N{{a}_{2}}C{{O}_{3}}\xrightarrow{{}}2C{{H}_{3}}COONa\]\[+C{{O}_{2}}+{{H}_{2}}O\] \[C{{H}_{3}}C{{H}_{2}}C{{H}_{3}}+5{{O}_{2}}\xrightarrow{{}}3C{{O}_{2}}+4{{H}_{2}}O\]You need to login to perform this action.
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