A) \[2\text{ }\times \text{ }{{10}^{12}}\]
B) \[~3\text{ }\times \text{ }{{10}^{12}}\]
C) \[2\text{ }\times \text{ }{{10}^{14}}\]
D) \[3\text{ }\times \text{ }{{10}^{14}}\]
Correct Answer: A
Solution :
As, \[q=ne\], \[n=\frac{3\,.\,2\times {{10}^{-7}}}{1\,.\,6\times {{10}^{-19}}}\] \[\Rightarrow \,\,n=2\times {{10}^{12}}\] electrons.You need to login to perform this action.
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