A) 62.5 mW
B) 625 mW
C) 6.25 mW
D) 12.5 mW
Correct Answer: C
Solution :
(c) 6.25 mW Here, \[l=0.1\,m,\,\,v=1\,m{{s}^{-1}}\] \[l=50\,\,A,B=1.25\,mT=1.25\times {{10}^{-3}}T\] The induced emf is \[\varepsilon =Blv\] The mechanical power is \[P=\varepsilon l=Blvl=1.25\times {{10}^{-3}}\times 0.1\times 1\times 50\] \[=6.25\times {{10}^{-3}}W=6.25\,\,mW\]You need to login to perform this action.
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