• # question_answer The value of $\cot y{}^\circ$ is: A) $\frac{7}{4}$ B) $\frac{4}{7}$ C) $\frac{\sqrt{65}}{4}$ D) $\frac{\sqrt{65}}{7}$

 In right $\Delta TSP$ $\cot y{}^\circ =\frac{Base}{Perpendicular}=\frac{PS}{TS}=\frac{7}{4}$ So, option [a] is correct.