A) 15m
B) 25m
C) 35m
D) 40m
Correct Answer: B
Solution :
[b] As per question, it can be shown as |
The displacement is the shortest path |
between initial and final position. |
\[\therefore \] Displacement =AC = \[\sqrt{A{{B}^{2}}+C{{B}^{2}}}\] |
= \[\sqrt{{{15}^{2}}+{{20}^{2}}}\]= 25 m |
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