A) \[Mo\]
B) \[Fe\]
C) \[Ni\]
D) \[Pt\]
Correct Answer: D
Solution :
\[4N{{H}_{3}}+5{{O}_{2}}\underset{1100K}{\mathop{\xrightarrow{Pt\,\,guage}}}\,4NO\xrightarrow{{{O}_{2}}}4N{{O}_{2}}\] \[\xrightarrow{2{{H}_{2}}O+{{O}_{2}}}4HN{{O}_{3}}\]You need to login to perform this action.
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