A) \[-\frac{2Q}{4\pi {{b}^{2}}},\frac{Q}{4\pi {{c}^{2}}}\]
B) \[-\frac{Q}{4\pi {{b}^{2}}},\frac{Q}{4\pi {{c}^{2}}}\]
C) \[0,\frac{Q}{4\pi {{c}^{2}}}\]
D) None of the above
Correct Answer: A
Solution :
(a) Surface charge density (s) \[=\frac{\text{Charge}}{\text{Surface area}}\] So \[{{\sigma }_{inner}}=\frac{-2Q}{\,4\pi {{b}^{2}}}\] and \[{{\sigma }_{Outer}}=\frac{Q}{\,4\pi {{c}^{2}}}\]You need to login to perform this action.
You will be redirected in
3 sec