A) Zero
B) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}^{2}}}{{{L}^{2}}}\]
C) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{3{{q}^{2}}}{{{L}^{2}}}\]
D) \[\frac{1}{12\pi {{\varepsilon }_{0}}}\frac{{{q}^{2}}}{{{L}^{2}}}\]
Correct Answer: A
Solution :
In the following figure since \[|\overrightarrow{{{F}_{A}}}|\,=\,|\overrightarrow{{{F}_{B}}}|\,=\,|\overrightarrow{{{F}_{C}}}|\] and they are equally inclined with each other, so their resultant will be zero.You need to login to perform this action.
You will be redirected in
3 sec