A) \[N{{O}_{2}}\]
B) \[FeS{{O}_{4}}N{{O}_{2}}\]
C) \[{{N}_{2}}O.FeS{{O}_{4}}\]
D) \[FeS{{O}_{4}}.NO\]
Correct Answer: D
Solution :
Nitrates on reaction with conc. \[{{H}_{2}}S{{O}_{4}}\] and \[FeS{{O}_{4}}\] give a brown ring due to formation of \[FeS{{O}_{4}}.NO\] or \[[Fe{{({{H}_{2}}O)}_{5}}NO]S{{O}_{4}}\].
You need to login to perform this action.
You will be redirected in
3 sec
