A) \[%N=\frac{1.4\text{ }V\text{ }W}{N}\]
B) \[%N=\frac{1.4\text{ }N\text{ }W}{V}\]
C) \[%N=\frac{V\text{ }N\text{ }W}{1.8}\]
D) \[%N=\frac{1.4\text{ }V\text{ }N}{W}\]
Correct Answer: D
Solution :
% of \[N=\frac{1.4\times V\times N}{W}\] where V = Volume of acid used N = Normality of acid, W = Weight of substanceYou need to login to perform this action.
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