A) \[{{C}_{4}}{{H}_{4}}{{O}_{5}}\]
B) \[{{C}_{10}}{{H}_{12}}\]
C) \[{{C}_{7}}{{O}_{3}}\]
D) \[{{C}_{6}}{{H}_{12}}{{O}_{3}}\]
E) \[{{C}_{4}}{{H}_{8}}{{O}_{5}}\]
Correct Answer: D
Solution :
Empirical formula weight \[{{C}_{2}}{{H}_{4}}O\] \[=(12\times 2+4+16)=44\] Molecular formula \[=\frac{\text{mol}\text{. wt}}{\text{eq}\text{. formula wt}\text{.}}\times \] Emp. Formula \[=\frac{132.1}{44}\times \text{Emperical formula}\] \[=3\times {{C}_{2}}{{H}_{4}}O={{C}_{6}}{{H}_{12}}{{O}_{3}}\]
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