A) \[CH\]
B) \[C{{H}_{2}}\]
C) \[C{{H}_{3}}\]
D) \[C{{H}_{4}}\]
Correct Answer: B
Solution :
\[\because \] 1.8gm water obtained from 1.4gm hydrocarbon \[\therefore \]18gm water obtained from - \[\frac{1.4}{1.8}\times 18=14\] gm. Empirical formula Mass = 14 \[\therefore \] Empirical formula = \[C{{H}_{2}}\].
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