A) 2.05
B) 8.2
C) 4.1
D) \[5\times 3.387\times {{10}^{-7}}\]
Correct Answer: C
Solution :
\[m=Zi\,t=Zq\]; \[q=\frac{5\times {{10}^{-3}}}{3.387\times {{10}^{-7}}}amp\text{-}sec\] or \[q=\frac{5\times {{10}^{-3}}}{3.387\times {{10}^{-7}}\times 3600}amp\text{-}hr=4.1\]You need to login to perform this action.
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