A) \[F{{e}^{3+}}\]
B) \[C{{u}^{2+}}\]
C) \[P{{b}^{2+}}\]
D) \[A{{g}^{+}}\]
Correct Answer: C
Solution :
Atom in highest oxidation state can oxidize iodide to liberate \[{{I}_{2}}\] which is volumetrically measured by iodometric titration using hypo. \[2{{I}^{-}}\to {{I}_{2}}\] \[P{{b}^{+2}}\to \] Lowest oxidation state can not oxidise iodide to \[{{I}_{2}}\].You need to login to perform this action.
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