A) \[(1-{{m}^{2}})({{a}^{2}}+{{b}^{2}})={{c}^{2}}\]
B) \[(1+{{m}^{2}})({{a}^{2}}-{{b}^{2}})={{c}^{2}}\]
C) \[(1-{{m}^{2}})({{a}^{2}}-{{b}^{2}})={{c}^{2}}\]
D) None of these
Correct Answer: B
Solution :
We know \[CD=\left| \frac{c}{\sqrt{1+{{m}^{2}}}} \right|\] ?.(i) But according to figure, \[{{a}^{2}}-{{b}^{2}}=C{{D}^{2}}\] From (i) and (ii), we get \[{{a}^{2}}-{{b}^{2}}=\frac{{{c}^{2}}}{(1+{{m}^{2}})}\] \[\Rightarrow ({{a}^{2}}-{{b}^{2}})(1+{{m}^{2}})={{c}^{2}}\].You need to login to perform this action.
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