question_answer

ABCD is a cyclic quadrilateral. AB and DC when produced meet at P, if PA = 8 cm, PB = 6 cm, PC = 4 cm, then the length (in cm) of PD is [SSC CGL Tier II, 2015]

A) 6

B) 10

C) 12

D) 8

Correct Answer: C

Solution :

[c] According to the questions \[PA=8\,cm\] and \[PC=4\,cm\] \[\because \]       \[PA\times PB=PD\times PC\] \[\Rightarrow \]   \[8\times 6=PD\times 4\] \[\therefore \]      \[PD=2\times 6=12\,cm\]