A) 8 cm
B) \[8\sqrt{2}\]
C) \[6\sqrt{6}\]
D) \[2\sqrt{6}\]
Correct Answer: C
Solution :
(c): \[{{C}_{1}}{{C}_{2}}=15R{{C}_{1}}=3\] \[\Rightarrow \] \[R{{C}_{2}}=\sqrt{{{15}^{2}}-{{3}^{2}}}=\sqrt{216}=6\sqrt{6}\] But \[\,R{{C}_{2}}=PQ=6\sqrt{6}\]
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