A) \[~\text{1}00{}^\circ \]
B) \[\text{12}0{}^\circ \]
C) \[~\text{9}0{}^\circ \]
D) \[~\text{11}0{}^\circ \]
Correct Answer: D
Solution :
AO is joined. Since the circle is the in circle for\[\Rightarrow \], AO, BO and CO are the angle bisectors of \[{{6}^{x}}\] and \[\therefore \]respectively. \[{{6}^{x}}\] \[{{x}^{3}}\] In \['x'\] From the figure, \[\text{(25}\times \text{7)cm}\] \[~(\text{2}\times \text{52}\times \text{73) cm}\]You need to login to perform this action.
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