• # question_answer In $\Delta \text{ABC},\text{ }\angle \text{B}=90{}^\circ$.If a circle drawn with AB as diameter intersects the hypotenuse AC at P, which of the following is true? A)  The tangent drawn to the circle at P bisects the side BC. B)  The tangent drawn to the circle at A bisects the side AB. C)  The tangent drawn to the circle at B bisects the side AC. D)  The tangent drawn to the circle at C bisects the side BC.

Solution :

Join P to B. Now, $=(\text{25}\times \text{7})\text{(2}\times {{\text{5}}^{\text{2}}}\times {{\text{7}}^{\text{3}}}\text{) c}{{\text{m}}^{\text{2}}}$ $={{\text{2}}^{\text{6}}}\times {{\text{5}}^{\text{2}}}\times {{\text{7}}^{\text{4}}}\text{c}{{\text{m}}^{\text{2}}}$ But $2-\sqrt{4}=2-2=0$ ${{(\sqrt{5})}^{2}}=5$ $\sqrt{9}-\sqrt{4}=3-2=1$ $\sqrt{2}-\sqrt{3}$ (from $1789=29x+49$) $'x'$ $\therefore$ $1789-49=29x$ $\Rightarrow$ MP=MC but, MP=MB            MC = MB Hence, the statement in option [a] is true.

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