question_answer

A neutral atom will have lowest ionization potential when its electronic configuration is

A) \[\text{1}{{\text{s}}^{\text{1}}}\]                           

B)         \[\text{1}{{\text{s}}^{\text{2}}},\text{ 2}{{\text{s}}^{\text{2}}},\text{ 2}{{\text{p}}^{\text{6}}}\]

C) \[\text{1}{{\text{s}}^{\text{2}}},\text{ 2}{{\text{s}}^{\text{2}}},\text{ 2}{{\text{p}}^{\text{2}}}\]        

D)        \[\text{1}{{\text{s}}^{\text{2}}},\text{ 2}{{\text{s}}^{\text{2}}},\text{ 2}{{\text{p}}^{\text{6}}},\text{ 3}{{\text{s}}^{\text{2}}},\text{ 3}{{\text{p}}^{\text{6}}}\]