A) 6
B) 7
C) 8
D) 5
Correct Answer: B
Solution :
The given points are collinear if the area of the triangle formed by the points is 0. \[QA\bot AB\] \[\text{PB}\bot \text{AB}\] \[\Delta \text{QAO}=\text{245 c}{{\text{m}}^{\text{2}}}\] \[\Delta \text{QAO}\] \[\Delta \text{PBO}\] \[\angle \text{QAO}=\angle \text{BPO},\text{ }\angle \text{AQO}=\angle \text{PBO}\]
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