• question_answer Find a point on the X-axis which is equidistant from the points (5, 4) and (-3, 3). A)  (2, 0)                     B)         (0, 3) C)  (-2, 2)                   D)         (3, 0)

Since, the required point (say P) is on the X-axis, its ordinate will be zero. Let the abscissa of the point be x. Therefore, coordinates of the point P are$\Rightarrow$. Let A and B denote the points (5, 4) and (-2, 3) respectively. Given that AP = BP, we have $\frac{x-4}{4}=\frac{3x-19}{x-3}$ i.e., $\Rightarrow$ $x=11\,or\,8$ $\therefore$ $'x'$ Thus, the required point is (2, 0).