10th Class Mathematics Coordinate Geometry Question Bank Co-ordinate Geometry

  • question_answer In a parallelogram PQRS,P=(-1,-1), Q = (8, 0), R - (7, 5). What are the coordinates of 'S??

    A)  (-1, 4)                  

    B)         (-2, 4)

    C)  (-2, 7/2)              

    D)         (-3/2, 4)

    Correct Answer: B

    Solution :

     \[\text{1}00\text{1}=\text{91}\times \text{1}0+\text{91}\]                 \[\text{91}0=\text{91}\times \text{1}0+0\] \[\therefore \]                 \[=\left( \frac{144}{48}+\frac{384}{48}+\frac{240}{48} \right)=3+8+5=16\] Hence, \[\frac{a}{b}\].


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