A) (0, 2)
B) \[\left( \text{1},\text{ 4} \right)\]
C) (2, 0)
D) \[\left( \text{2},\text{ 1} \right)\]
Correct Answer: D
Solution :
We know that he point on the line satisfies the equation (graph) of the line. Now, we are given that the equation of the line is, \[3x-2y=4.\] So, we check that which of the value satisfies the graph (equation) \[(0,2)\,\,\,:\,\,\,3(0)-2(2)=-4\] \[(2,1)\,\,\,:\,\,\,3(2)-2(1)=4\] \[(1,4)\,\,\,:\,\,\,3(1)-2(4)=-5\] \[(2,0)\,\,\,:\,\,\,3(2)-2(1)=6\] \[(2,4)\,\,\,:\,\,\,3(2)-2(4)=-2\] As, we can see from above that \[(2,1)\] satisfies the equation of a line, so, point \[(2,1)\] is on the graph of\[3x-2y=4\].
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